Minimum Value in a Range |
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This Min() function is used to find the maximum value in a list |
#include <iostream> using namespace std; int Min(const int *Numbers, const int Count) { int Minimum = Numbers[0]; for(int i = 0; i < Count; i++) if( Minimum > Numbers[i] ) Minimum = Numbers[i]; return Minimum; } double Min(const double *Numbers, const int Count) { double Minimum = Numbers[0]; for(int i = 0; i < Count; i++) if( Minimum > Numbers[i] ) Minimum = Numbers[i]; return Minimum; } int main() { int Nbrs[] = { 12, 483, 748, 35, 478 }; int Total = sizeof(Nbrs) / sizeof(int); int Minimum = Min(Nbrs, Total); cout << "Minimum: " << Minimum << endl; return 0; }
Here is an example of running the program:
Minimum: 12
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