C++ Examples: Returning a Reference |
|
As a function can be created to return a value of a primitive type, a function can also be defined to return a reference to a primitive type. When declaring such a function, you must indicate that it is returning a reference by preceding it with the & operator. Here is an example: double & GetWeeklyHours() { } In the body of the function, defined the desired behavior of the function as you see fit. The most important rule to apply is that the function must return not only a reference but a reference to the appropriate type. When returning the value, don't precede the name of the variable with &. Here is an example: double & GetWeeklyHours() { double h = 46.50; double &hours = h; return hours; } When calling a function that returns a reference, you can proceed as if it returns a regular value but of the appropriate type. Here is an example: //--------------------------------------------------------------------------- #include <iostream> using namespace std; double & GetWeeklyHours() { double h = 46.50; double &hours = h; return hours; } //--------------------------------------------------------------------------- int main() { double hours = GetWeeklyHours(); cout << "Weekly Hours: " << hours << endl; return 0; } //--------------------------------------------------------------------------- This would produce: Weekly Hours: 46.5 |
|
||
Home | Copyright © 2006-2016, FunctionX, Inc. | |
|