After creating the class, you can declare a variable of it and serialize it, using either the binary or the SOAP approach. Here is an example:

using System;
using System.IO;
using System.Runtime.Serialization.Formatters.Binary;

[Serializable]
public class Car
{
    public string Make;
    public string Model;

    // Because the value of a car can change,
    // there is no reason to save it
    [NonSerialized]
    public decimal Value;
    public uint Year;
    public byte Color;
}

public class Exercise
{
    static int Main(string[] args)
    {
        var vehicle = new Car();

        vehicle.Make = "Lexus";
        vehicle.Model = "LS";
        vehicle.Year = 2007;
        vehicle.Color = 4;
        vehicle.Value = 28640M;

        var stmCar = new FileStream("Car1.car", FileMode.Create);
        var bfmCar = new BinaryFormatter();

        bfmCar.Serialize(stmCar, vehicle);


        return 0;
    }
}

You can then retrieve the object and its values, using any of the techniques we learned earlier. Here is an example:

using System;
using System.IO;
using System.Runtime.Serialization.Formatters.Binary;

[Serializable]
public class Car
{
    public string Make;
    public string Model;

    // Because the value of a car can change,
    // there is no reason to save it
    [NonSerialized]
    public decimal Value;
    public uint Year;
    public byte Color;
}

public class Exercise
{
    static int Main(string[] args)
    {
        var stmCar = new FileStream("Car1.car", FileMode.Open);
        var bfmCar = new BinaryFormatter();
        var vehicle = (Car)bfmCar.Deserialize(stmCar);

        Console.WriteLine("Car Information");
        Console.WriteLine("Make: {0}", vehicle.Make);
        Console.WriteLine("Model: {0}", vehicle.Model);
        Console.WriteLine("Year: {0}", vehicle.Year);
        Console.Write("Color: ");
        switch (vehicle.Color)
        {
            case 1:
                Console.WriteLine("Black");
                break;
            case 2:
                Console.WriteLine("Gray");
                break;
            case 3:
                Console.WriteLine("White");
                break;
            case 4:
                Console.WriteLine("Red");
                break;
            case 5:
                Console.WriteLine("Blue");
                break;
        }
        Console.WriteLine("Value:  {0}\n", vehicle.Value);

        return 0;
    }
}

This would produce:

Car Information
Make: Lexus
Model: LS
Year: 2007
Color: Red
Value:  0

Press any key to continue . . .

Notice that the value of the Value field was not saved: it holds the default value of its data type. This indicates that, you can assign a value a [NonSerialized] field and save the object. The value of that field would not be saved but the compiler would not throw an exception.