Details on Serialization |
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In the examples we have used so far, we were saving the whole object. You can make it possible to save only some parts of the class. When creating a class, you can specify what fields would be serialized and which ones would not be. To specify that a member cannot be saved, you can mark it with the [NonSerialized] attribute. Here is an example: [Serializable] public class Car { public string Make; public string Model; // Because the value of a car can change, // there is no reason to save it [NonSerialized] public decimal Value; public uint Year; public byte Color; } |
After creating the class, you can declare a variable of it and serialize it, using either the binary or the SOAP approach. Here is an example: using System; using System.IO; using System.Runtime.Serialization.Formatters.Binary; [Serializable] public class Car { public string Make; public string Model; // Because the value of a car can change, // there is no reason to save it [NonSerialized] public decimal Value; public uint Year; public byte Color; } class Program { static int Main(string[] args) { Car vehicle = new Car(); vehicle.Make = "Lexus"; vehicle.Model = "LS"; vehicle.Year = 2007; vehicle.Color = 4; vehicle.Value = 28640M; FileStream stmCar = new FileStream("Car1.car", FileMode.Create); BinaryFormatter bfmCar = new BinaryFormatter(); bfmCar.Serialize(stmCar, vehicle); return 0; } } You can then retrieve the object and its values, using any of the techniques we learned earlier. Here is an example: using System; using System.IO; using System.Runtime.Serialization.Formatters.Binary; [Serializable] public class Car { public string Make; public string Model; // Because the value of a car can change, // there is no reason to save it [NonSerialized] public decimal Value; public uint Year; public byte Color; } class Program { static int Main(string[] args) { FileStream stmCar = new FileStream("Car1.car", FileMode.Open); BinaryFormatter bfmCar = new BinaryFormatter(); Car vehicle = (Car)bfmCar.Deserialize(stmCar); Console.WriteLine("Car Information"); Console.WriteLine("Make: {0}", vehicle.Make); Console.WriteLine("Model: {0}", vehicle.Model); Console.WriteLine("Year: {0}", vehicle.Year); Console.Write("Color: "); switch (vehicle.Color) { case 1: Console.WriteLine("Black"); break; case 2: Console.WriteLine("Gray"); break; case 3: Console.WriteLine("White"); break; case 4: Console.WriteLine("Red"); break; case 5: Console.WriteLine("Blue"); break; } Console.WriteLine("Value: {0}\n", vehicle.Value); return 0; } } This would produce: Car Information Make: Lexus Model: LS Year: 2007 Color: Red Value: 0 Press any key to continue . . . Notice that the value of the Value field was not saved: it holds the default value of its data type. This indicates that, you can assign a value a [NonSerialized] field and save the object. The value of that field would not be saved but the compiler would not throw an exception.
To support serialization, the .NET Framework provides the ISerializable interface. You can create a class that implements this interface to customize the serialization process. Even if you plan to use this interface, the class you create must be marked with the [Serializable] attribute.
The .NET Framework is filled with many classes ready for serialization. To know that a class is ready for serialization, when viewing its documentation either in the MSDN web site or in the help documentation, check that it is marked with the [SerializableAttribute]. Here is an example of such as class: Some of these classes provide the properties and methods to create an object and directly save it. For some other classes, you must first create a class, mark it with the [Serializable] attribute, build an object of it, and then pass it to the .NET class. |
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